BEGIN:VCALENDAR VERSION:2.0 PRODID:-//Architecture - ECPv6.16.3//NONSGML v1.0//EN CALSCALE:GREGORIAN METHOD:PUBLISH X-ORIGINAL-URL:https://quiz.gatearchitecture.co.in X-WR-CALDESC:Events for Architecture REFRESH-INTERVAL;VALUE=DURATION:PT1H X-Robots-Tag:noindex X-PUBLISHED-TTL:PT1H BEGIN:VTIMEZONE TZID:Asia/Kolkata BEGIN:STANDARD TZOFFSETFROM:+0530 TZOFFSETTO:+0530 TZNAME:IST DTSTART:20250101T000000 END:STANDARD END:VTIMEZONE BEGIN:VEVENT DTSTART;VALUE=DATE:20260529 DTEND;VALUE=DATE:20260530 DTSTAMP:20260602T001407 CREATED:20260524T103733Z LAST-MODIFIED:20260524T103733Z UID:237-1780012800-1780099199@quiz.gatearchitecture.co.in SUMMARY:Architecture Daily Quiz - Attempt Now DESCRIPTION:/5\n \n \n \n 1\n \n \n \n \n \n \n \n \n \n \n GATE Architecture & Govt. Jobs \n \n\n\n\nPrepare for GATE Architecture & Planning (AR) 2027-28 with free online quizzes and mock tests by KP GATE Classes. Practice Architecture MCQs\, PYQs\, Planning\, Structures\, Building Materials\, and Government Architecture Exam questions with instant answers and real exam-level practice. \n\n\n\n\n\n\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n The main cable of a suspension bridge supports the deck with hangars.\nThese hangars are equidistant along the length of the bridge and represent a\nuniformly distributed load. Assuming the cable to be weightless as compared\nto the applied loading\, the best approximation of the shape that the cable\ntakes for this loading is a . \n\n \n \n \n \n \n\n \n\n Catenary curve\n\n \n \n \n\n \n\n Parabolic curve\n\n \n \n \n\n \n\n Circular arc\n\n \n \n \n\n \n\n Hyperbolic curve\n\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n Explanation: Despite their visual similarities\, catenaries and parabolas are two\nvery different curves\, both conceptually and mathematically. A catenary curve is\ncreated by its own weight\, pulling down because of gravity. The parabolic curves\nof the suspension cable are not created by gravity alone\, but also by other forces:\ncompression and tension acting on it. Also\, the weight of the suspension cable is\nnegligible compared to that of the deck\, but it is also supporting the weight of the\ndeck. This is also another conceptual reason why the suspension cables hang in\na parabolic curve. \n\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n Sidi Bashir Mosque with ‘Shaking Minaret’ is in \n\n \n \n \n \n \n\n \n\n Amritsar\n\n \n \n \n\n \n\n Ajmer\n\n \n \n \n\n \n\n Ahmadabad\n\n \n \n \n\n \n\n Allahabad\n\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n Sidi Bashir Mosque was located in the city of Ahmedabad\, Gujarat. Due\nto its unique construction\, the minarates of mosque are also called Jhulta Minar\nor Shaking Minarets. \n\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n Which of the following is a Vector Graphics Software? \n\n \n \n \n \n \n\n \n\n Odeon\n\n \n \n \n\n \n\n Inkscape\n\n \n \n \n\n \n\n Design Builder\n\n \n \n \n\n \n\n Adobe Dreamweaver\n\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n Inkscape is a free and open-source vector graphics editor used to\ncreate vector images\, primarily in Scalable Vector Graphics format. Other formats can be imported and exported. Inkscape can render primitive vector shapes and text. \n\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n ‘Area based development’ and ‘Pan City development’ are part of \n\n \n \n \n \n \n\n \n\n Smart city mission\n\n \n \n \n\n \n\n Atal Innovation Mission\n\n \n \n \n\n \n\n Swachh Bharat mission\n\n \n \n \n\n \n\n Digital India mission\n\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n two strategic component of smart city mission i.e. Area\nbased development and Pan city development. Under area based development\nwe have Retrofitting\, redevelopment and Greenfield development. \n\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n The Golden Ratio refers to . \n\n \n \n \n \n \n\n \n\n 16:9\n\n \n \n \n\n \n\n 1:√2\n\n \n \n \n\n \n\n 1:1\n\n \n \n \n\n \n\n 2:(1 + √5)\n\n \n \n \n \n \n \n \n \n \n \n \n \n \n Golden ratio\, also known as the golden section\, golden mean\, or\ndivine proportion\, in mathematics\, the irrational number (1 + Square root of√5)/2\,\noften denoted by the Greek letter ϕ or τ\, which is approximately equal to 1.618. \n\n \n \n \n \n \n \n \n \n \n Congratulations! You’ve completed the test. Fill out the form to view your result. \n\n \n \n \n \n \n \n \n Your score is The average score is 40% Follow Us\n\n \n \n \n \n \n \n \n \n \n 0%\n \n \n \n \n \n Restart quiz URL:https://quiz.gatearchitecture.co.in/quiz/architecture-daily-quiz-10/ END:VEVENT END:VCALENDAR